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A right circular cylinder is circumscrib...

A right circular cylinder is circumscribed about a hemisphere so that they share the same base. The ratio of the volumes of cylinder and hemisphere is

A

`4:3`

B

`3:1`

C

`3:4`

D

`3:2`

Text Solution

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The correct Answer is:
To find the ratio of the volumes of a right circular cylinder and a hemisphere that share the same base, we can follow these steps: ### Step 1: Define the radius and height Let the radius of the base of both the cylinder and the hemisphere be \( R \). Since the cylinder is circumscribed about the hemisphere, the height of the cylinder will also be equal to the radius of the hemisphere, which is \( R \). ### Step 2: Calculate the volume of the cylinder The volume \( V_c \) of a cylinder is given by the formula: \[ V_c = \pi R^2 H \] Substituting \( H = R \): \[ V_c = \pi R^2 \cdot R = \pi R^3 \] ### Step 3: Calculate the volume of the hemisphere The volume \( V_h \) of a hemisphere is given by the formula: \[ V_h = \frac{2}{3} \pi R^3 \] ### Step 4: Find the ratio of the volumes Now, we need to find the ratio of the volume of the cylinder to the volume of the hemisphere: \[ \text{Ratio} = \frac{V_c}{V_h} = \frac{\pi R^3}{\frac{2}{3} \pi R^3} \] ### Step 5: Simplify the ratio The \( \pi R^3 \) terms cancel out: \[ \text{Ratio} = \frac{1}{\frac{2}{3}} = \frac{3}{2} \] ### Conclusion The ratio of the volumes of the cylinder to the hemisphere is: \[ \frac{3}{2} \]
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