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The base of a right prism is a trapezium...

The base of a right prism is a trapezium whose lengths of two parallel sides are 10 cm and 6 cm and distance between them is 5 cm. If the height of the prism is 8 cm, its volume is

A

`320 cm^(3)`

B

`300.5 cm^(3)`

C

`310 cm^(3)`

D

`300 cm^(3)`

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The correct Answer is:
To find the volume of the right prism with a trapezium as its base, we can follow these steps: ### Step 1: Calculate the Area of the Trapezium The formula for the area of a trapezium (trapezoid) is given by: \[ \text{Area} = \frac{(l_1 + l_2) \times d}{2} \] Where: - \( l_1 \) = length of the first parallel side = 10 cm - \( l_2 \) = length of the second parallel side = 6 cm - \( d \) = distance between the parallel sides = 5 cm Substituting the values into the formula: \[ \text{Area} = \frac{(10 + 6) \times 5}{2} \] Calculating the sum of the lengths of the parallel sides: \[ 10 + 6 = 16 \] Now substituting back into the area formula: \[ \text{Area} = \frac{16 \times 5}{2} = \frac{80}{2} = 40 \text{ cm}^2 \] ### Step 2: Calculate the Volume of the Prism The volume \( V \) of a prism is calculated using the formula: \[ V = \text{Base Area} \times \text{Height} \] Where: - Base Area = 40 cm² (calculated in Step 1) - Height = 8 cm Substituting the values into the formula: \[ V = 40 \times 8 = 320 \text{ cm}^3 \] ### Final Answer The volume of the right prism is \( 320 \text{ cm}^3 \). ---
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