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The diameters of two cylinders are in th...

The diameters of two cylinders are in the ratio 3:2 and their volumes are equal. The ratio of their heights is

A

`2:3`

B

`3:2`

C

`9:4`

D

`4:9`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the ratio of the heights of two cylinders given that their diameters are in the ratio of 3:2 and their volumes are equal. ### Step-by-Step Solution: 1. **Define the Diameters and Radii**: - Let the diameter of the first cylinder (D1) be \(3x\). - Therefore, the radius of the first cylinder (r1) is \( \frac{3x}{2} \). - Let the diameter of the second cylinder (D2) be \(2x\). - Therefore, the radius of the second cylinder (r2) is \( \frac{2x}{2} = x \). 2. **Volume of the Cylinders**: - The volume (V) of a cylinder is given by the formula: \[ V = \pi r^2 h \] - For the first cylinder, the volume (V1) can be expressed as: \[ V_1 = \pi \left(\frac{3x}{2}\right)^2 h_1 = \pi \left(\frac{9x^2}{4}\right) h_1 \] - For the second cylinder, the volume (V2) can be expressed as: \[ V_2 = \pi (x^2) h_2 \] 3. **Set the Volumes Equal**: - Since the volumes are equal, we set \(V_1\) equal to \(V_2\): \[ \pi \left(\frac{9x^2}{4}\right) h_1 = \pi (x^2) h_2 \] 4. **Cancel Out Common Terms**: - We can cancel \(\pi\) from both sides: \[ \frac{9x^2}{4} h_1 = x^2 h_2 \] - Next, we can cancel \(x^2\) from both sides (assuming \(x \neq 0\)): \[ \frac{9}{4} h_1 = h_2 \] 5. **Rearranging for Height Ratio**: - Rearranging gives us: \[ h_1 = \frac{4}{9} h_2 \] - To find the ratio of the heights \(h_1:h_2\), we can express it as: \[ \frac{h_1}{h_2} = \frac{4}{9} \] 6. **Final Ratio**: - Thus, the ratio of the heights \(h_1:h_2\) is \(4:9\). ### Conclusion: The ratio of the heights of the two cylinders is \(4:9\).
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