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The radius of the base of a right circul...

The radius of the base of a right circular cone is 6 cm and its slant height is 10 cm. Then its volume is (Use `pi = (22)/(7)`)

A

a) `301.71 cm^(3)`

B

b) `310.71 cm^(3)`

C

c) `301.17 cm^(3)`

D

d) `310.17 cm^(3)`

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AI Generated Solution

The correct Answer is:
To find the volume of a right circular cone, we can use the formula: \[ \text{Volume} = \frac{1}{3} \pi r^2 h \] where: - \( r \) is the radius of the base, - \( h \) is the height of the cone, - \( \pi \) is approximately \( \frac{22}{7} \). ### Step 1: Identify the given values - Radius \( r = 6 \, \text{cm} \) - Slant height \( l = 10 \, \text{cm} \) ### Step 2: Find the height of the cone To find the height \( h \) of the cone, we can use the Pythagorean theorem. The relationship between the radius, height, and slant height is given by: \[ l^2 = r^2 + h^2 \] Substituting the known values: \[ 10^2 = 6^2 + h^2 \] Calculating the squares: \[ 100 = 36 + h^2 \] Rearranging to find \( h^2 \): \[ h^2 = 100 - 36 = 64 \] Taking the square root to find \( h \): \[ h = \sqrt{64} = 8 \, \text{cm} \] ### Step 3: Substitute the values into the volume formula Now that we have \( h \), we can substitute \( r \) and \( h \) into the volume formula: \[ \text{Volume} = \frac{1}{3} \times \frac{22}{7} \times (6^2) \times 8 \] Calculating \( 6^2 \): \[ 6^2 = 36 \] Now substituting back into the volume formula: \[ \text{Volume} = \frac{1}{3} \times \frac{22}{7} \times 36 \times 8 \] ### Step 4: Simplify the expression Calculating the multiplication: \[ 36 \times 8 = 288 \] Now substituting this back into the volume formula: \[ \text{Volume} = \frac{1}{3} \times \frac{22}{7} \times 288 \] Calculating \( \frac{288}{3} \): \[ \frac{288}{3} = 96 \] Now substituting this value: \[ \text{Volume} = \frac{22}{7} \times 96 \] ### Step 5: Final calculation Calculating \( 22 \times 96 \): \[ 22 \times 96 = 2112 \] Now dividing by 7: \[ \text{Volume} = \frac{2112}{7} \approx 301.71 \, \text{cm}^3 \] ### Conclusion Thus, the volume of the cone is approximately: \[ \text{Volume} \approx 301.71 \, \text{cm}^3 \]
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