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The perimeter of a triangle is 40 cm and...

The perimeter of a triangle is 40 cm and its area is `60 cm^(2)`. If the largest side measures 17 cm, then the length (in cm) of the smallest side of the triangle is

A

4

B

6

C

8

D

15

Text Solution

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The correct Answer is:
To solve the problem, we need to find the length of the smallest side of a triangle given the perimeter, area, and the length of the largest side. ### Step-by-Step Solution: 1. **Identify the given values:** - Perimeter of the triangle (P) = 40 cm - Area of the triangle (A) = 60 cm² - Length of the largest side (c) = 17 cm 2. **Let the lengths of the other two sides be a and b.** - According to the perimeter, we have: \[ a + b + c = 40 \] Substituting the value of c: \[ a + b + 17 = 40 \] Simplifying this gives: \[ a + b = 23 \quad \text{(Equation 1)} \] 3. **Use the area formula for a triangle:** - The area of a triangle can also be expressed using Heron's formula: \[ A = \sqrt{s(s-a)(s-b)(s-c)} \] where \( s \) is the semi-perimeter: \[ s = \frac{P}{2} = \frac{40}{2} = 20 \] - Therefore, we can write: \[ A = \sqrt{20(20-a)(20-b)(20-17)} \] Simplifying gives: \[ A = \sqrt{20(20-a)(20-b)(3)} \] Setting this equal to the area: \[ 60 = \sqrt{60(20-a)(20-b)} \] Squaring both sides: \[ 3600 = 60(20-a)(20-b) \] Dividing both sides by 60: \[ 60 = (20-a)(20-b) \quad \text{(Equation 2)} \] 4. **Substituting from Equation 1 into Equation 2:** - We know \( b = 23 - a \). Substitute this into Equation 2: \[ 60 = (20-a)(20-(23-a)) \] Simplifying gives: \[ 60 = (20-a)(a-3) \] Expanding this: \[ 60 = 20a - a^2 - 60 + 3a \] Rearranging gives: \[ a^2 - 23a + 120 = 0 \] 5. **Solving the quadratic equation:** - We can use the quadratic formula: \[ a = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Here, \( a = 1, b = -23, c = 120 \): \[ a = \frac{23 \pm \sqrt{(-23)^2 - 4 \cdot 1 \cdot 120}}{2 \cdot 1} \] \[ a = \frac{23 \pm \sqrt{529 - 480}}{2} \] \[ a = \frac{23 \pm \sqrt{49}}{2} \] \[ a = \frac{23 \pm 7}{2} \] This gives us two possible values for \( a \): \[ a = \frac{30}{2} = 15 \quad \text{or} \quad a = \frac{16}{2} = 8 \] 6. **Finding the smallest side:** - If \( a = 15 \), then \( b = 23 - 15 = 8 \). - If \( a = 8 \), then \( b = 23 - 8 = 15 \). - Therefore, the smallest side is \( 8 \) cm. ### Final Answer: The length of the smallest side of the triangle is **8 cm**.
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