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A parallelopiped whose sides are in rati...

A parallelopiped whose sides are in ratio `2:4:8` have the same volume as a cube. The ratio of their surface area is :

A

`7:5`

B

`4:3`

C

`8:5`

D

`7:6`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the ratio of the surface area of a parallelepiped with sides in the ratio 2:4:8 to the surface area of a cube that has the same volume as the parallelepiped. ### Step-by-step Solution: 1. **Define the sides of the parallelepiped**: Given the sides are in the ratio 2:4:8, we can express the sides as: - Length = \(2x\) - Width = \(4x\) - Height = \(8x\) 2. **Calculate the volume of the parallelepiped**: The volume \(V\) of a parallelepiped is given by the product of its sides: \[ V = \text{Length} \times \text{Width} \times \text{Height} = (2x) \times (4x) \times (8x) = 64x^3 \] 3. **Define the side of the cube**: Let the side of the cube be \(y\). 4. **Set the volumes equal**: Since the volume of the cube is equal to the volume of the parallelepiped, we have: \[ y^3 = 64x^3 \] 5. **Solve for \(y\)**: Taking the cube root of both sides, we find: \[ y = \sqrt[3]{64x^3} = 4x \] 6. **Calculate the surface area of the parallelepiped**: The surface area \(S\) of a parallelepiped is given by: \[ S = 2(\text{Length} \times \text{Width} + \text{Width} \times \text{Height} + \text{Height} \times \text{Length}) \] Substituting the values: \[ S = 2((2x)(4x) + (4x)(8x) + (8x)(2x)) \] Calculating each term: - \( (2x)(4x) = 8x^2 \) - \( (4x)(8x) = 32x^2 \) - \( (8x)(2x) = 16x^2 \) Adding these: \[ S = 2(8x^2 + 32x^2 + 16x^2) = 2(56x^2) = 112x^2 \] 7. **Calculate the surface area of the cube**: The surface area \(S_c\) of a cube is given by: \[ S_c = 6y^2 \] Substituting \(y = 4x\): \[ S_c = 6(4x)^2 = 6 \times 16x^2 = 96x^2 \] 8. **Find the ratio of the surface areas**: The ratio of the surface area of the parallelepiped to the surface area of the cube is: \[ \text{Ratio} = \frac{S}{S_c} = \frac{112x^2}{96x^2} = \frac{112}{96} = \frac{7}{6} \] ### Final Answer: The ratio of the surface area of the parallelepiped to the surface area of the cube is \( \frac{7}{6} \).
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