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A figure has a square of side 40 cm wih ...

A figure has a square of side 40 cm wih an circle in a circumcircle. The area of the region between the incircle and the circumcircle is (in `cm^(2)`)

A

`100pi`

B

`200(pi - 2)`

C

`400pi`

D

`400(pi-1)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the area of the region between the incircle and the circumcircle of a square with a side length of 40 cm. ### Step-by-Step Solution: 1. **Identify the side length of the square**: The side length of the square is given as 40 cm. 2. **Calculate the radius of the incircle**: The radius of the incircle (r) of a square is half the side length. \[ r = \frac{\text{side}}{2} = \frac{40}{2} = 20 \text{ cm} \] 3. **Calculate the diagonal of the square**: The diagonal (d) of the square can be calculated using the formula: \[ d = a\sqrt{2} = 40\sqrt{2} \text{ cm} \] 4. **Calculate the radius of the circumcircle**: The radius (R) of the circumcircle is half the diagonal. \[ R = \frac{d}{2} = \frac{40\sqrt{2}}{2} = 20\sqrt{2} \text{ cm} \] 5. **Calculate the area of the incircle**: The area (A1) of the incircle is given by the formula: \[ A1 = \pi r^2 = \pi (20)^2 = 400\pi \text{ cm}^2 \] 6. **Calculate the area of the circumcircle**: The area (A2) of the circumcircle is given by the formula: \[ A2 = \pi R^2 = \pi (20\sqrt{2})^2 = \pi (400 \cdot 2) = 800\pi \text{ cm}^2 \] 7. **Calculate the area of the region between the incircle and circumcircle**: The area of the region between the incircle and circumcircle is: \[ \text{Area} = A2 - A1 = 800\pi - 400\pi = 400\pi \text{ cm}^2 \] ### Final Answer: The area of the region between the incircle and the circumcircle is \( 400\pi \text{ cm}^2 \). ---
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