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The diagonals of a rhombus are 8cm and 1...

The diagonals of a rhombus are 8cm and 15cm respectively. The perimeter (in cm) of the rhombus:

A

a. 60

B

b. 120

C

c. 68

D

d. 34

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The correct Answer is:
To find the perimeter of a rhombus when the lengths of its diagonals are given, we can follow these steps: ### Step 1: Identify the lengths of the diagonals Let the lengths of the diagonals be: - Diagonal 1 (d1) = 8 cm - Diagonal 2 (d2) = 15 cm ### Step 2: Use the relationship between the diagonals and the sides of the rhombus The relationship between the diagonals and the side of a rhombus is given by the formula: \[ d1^2 + d2^2 = 4a^2 \] where \( a \) is the length of a side of the rhombus. ### Step 3: Substitute the values of the diagonals into the formula Substituting the values of the diagonals into the formula: \[ 8^2 + 15^2 = 4a^2 \] ### Step 4: Calculate the squares of the diagonals Calculating the squares: \[ 8^2 = 64 \] \[ 15^2 = 225 \] ### Step 5: Add the squares of the diagonals Now, add the squares: \[ 64 + 225 = 289 \] So, we have: \[ 289 = 4a^2 \] ### Step 6: Solve for \( a^2 \) To find \( a^2 \), divide both sides by 4: \[ a^2 = \frac{289}{4} \] ### Step 7: Take the square root to find \( a \) Now, take the square root of both sides: \[ a = \sqrt{\frac{289}{4}} = \frac{\sqrt{289}}{\sqrt{4}} = \frac{17}{2} \] ### Step 8: Calculate the side length Thus, the side length \( a \) is: \[ a = 17 \text{ cm} \] ### Step 9: Calculate the perimeter The perimeter \( P \) of the rhombus is given by: \[ P = 4a \] Substituting the value of \( a \): \[ P = 4 \times 17 = 68 \text{ cm} \] ### Final Answer The perimeter of the rhombus is **68 cm**. ---
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