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Two pipes A & B can fill a tank in 15hr....

Two pipes A & B can fill a tank in 15hr. & 20hr. respectively while pipe C can empty the completely filled tank 25hr. Three pipes are opened simultaneously. After 10hr. pipe C is closed. After what time will the tank be completely filled ?

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The correct Answer is:
To solve the problem step by step, we will follow these procedures: ### Step 1: Determine the total work done by each pipe. - Pipe A can fill the tank in 15 hours, so its work rate is \( \frac{1}{15} \) of the tank per hour. - Pipe B can fill the tank in 20 hours, so its work rate is \( \frac{1}{20} \) of the tank per hour. - Pipe C can empty the tank in 25 hours, so its work rate is \( -\frac{1}{25} \) of the tank per hour (negative because it empties). ### Step 2: Calculate the Least Common Multiple (LCM) to find a common work unit. - The LCM of 15, 20, and 25 is 300. This means we can consider the tank as having a capacity of 300 units. ### Step 3: Calculate the efficiency of each pipe in terms of units per hour. - Efficiency of Pipe A: \[ \text{Efficiency of A} = \frac{300}{15} = 20 \text{ units/hour} \] - Efficiency of Pipe B: \[ \text{Efficiency of B} = \frac{300}{20} = 15 \text{ units/hour} \] - Efficiency of Pipe C: \[ \text{Efficiency of C} = -\frac{300}{25} = -12 \text{ units/hour} \] ### Step 4: Calculate the combined efficiency of all three pipes when they are open. - Combined efficiency when A, B, and C are open: \[ \text{Total Efficiency} = 20 + 15 - 12 = 23 \text{ units/hour} \] ### Step 5: Calculate the amount of work done in the first 10 hours. - Work done in 10 hours: \[ \text{Work done} = 23 \times 10 = 230 \text{ units} \] ### Step 6: Determine how much work is left to fill the tank. - Total work to fill the tank is 300 units, so the remaining work is: \[ \text{Remaining Work} = 300 - 230 = 70 \text{ units} \] ### Step 7: Calculate the combined efficiency of pipes A and B after pipe C is closed. - Combined efficiency of A and B: \[ \text{Efficiency of A and B} = 20 + 15 = 35 \text{ units/hour} \] ### Step 8: Calculate the time required to finish the remaining work. - Time required to fill the remaining 70 units: \[ \text{Time} = \frac{70}{35} = 2 \text{ hours} \] ### Final Answer: After pipe C is closed, it will take an additional 2 hours for the tank to be completely filled. ---
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MAHENDRA-PIPE & CISTERN-EXERCISE
  1. Two pipes A & B can fill a tank in 15hr. & 20hr. respectively while pi...

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  2. One tap can fill a cistern in 2 hours and another can other can empty ...

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  3. A tap can fill a tank in 25 minutes and another can empty it in 50 mi...

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  4. Two taps A and B can fill a tank in 10 hours and 15 hours, respectivel...

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  5. Two pipes A and B can separately empty a cistern in 12 hours and 15 ho...

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  6. Two pipes can fill a tank in 10 hours and 12 hours respectively. While...

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  7. Two pipes A and B can fill a cistern in 24 minutes and 30 minutes, res...

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  8. A cistern has a leak which would empty in 8 hours. A tap is turned on ...

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  9. If two pipes function simultaneously, a tank is filled in 12 hours. On...

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  10. One fill pipe A is 3 times faster than second fill pipe B and takes 32...

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  11. Two pipes A and B can fill a cistern in 4 minutes and 6 minutes respec...

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  12. There are two taps to fill a tank while a third to empty it. When the ...

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  13. A cistern is provided by two taps A and B. A can fill it in 20 minutes...

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  14. Two pipes A and B can separately fill a tank in 6 hours and 8 hours , ...

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  15. A cistern has two taps which fill it in 12 minutes and 15 mintues resp...

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  16. Two taps can separately fill a cistern in 10 minutes and 15 minutes re...

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  17. A water tank is 2/5 th full. Pipe A can fill the tank in 10 minutes an...

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  18. Tap 'A' can fill a water tank in 25 minutes , tap 'B' can fill the sam...

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  19. A pipe can fill a tank in 5 hours and a second pipe can empty it in 4 ...

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  20. A pump can fill a tank with water in 2 hours. Because of a leak in the...

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  21. Two pipe A and B can separately fill a cistern in 60 minutes and 75 mi...

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