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One tap can fill a cistern in 2 hours an...

One tap can fill a cistern in 2 hours and another can other can empty the cistern in 3 hours. How long will they take to fill the cistern if both the taps are opened ?

A

6 hours

B

7 hours

C

6 :30 hours

D

7:30 hours

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to determine how long it will take to fill the cistern when both taps are opened. ### Step-by-Step Solution: 1. **Identify the rates of the taps:** - Tap A (filling tap) can fill the cistern in 2 hours. - Tap B (emptying tap) can empty the cistern in 3 hours. 2. **Calculate the work done by each tap in one hour:** - The amount of work done by Tap A in one hour is: \[ \text{Efficiency of A} = \frac{1 \text{ cistern}}{2 \text{ hours}} = \frac{1}{2} \text{ cistern per hour} \] - The amount of work done by Tap B in one hour is: \[ \text{Efficiency of B} = \frac{1 \text{ cistern}}{3 \text{ hours}} = \frac{1}{3} \text{ cistern per hour} \] 3. **Convert the efficiencies to a common unit:** - To make calculations easier, we can find a common unit. The least common multiple (LCM) of 2 and 3 is 6. Thus, we can consider the total work in terms of 6 units (the capacity of the cistern). - The efficiency of Tap A in terms of 6 units is: \[ \text{Efficiency of A} = \frac{6}{2} = 3 \text{ units per hour} \] - The efficiency of Tap B in terms of 6 units is: \[ \text{Efficiency of B} = \frac{6}{3} = 2 \text{ units per hour} \] 4. **Determine the net efficiency when both taps are open:** - Since Tap A is filling and Tap B is emptying, we subtract the efficiency of Tap B from Tap A: \[ \text{Net Efficiency} = \text{Efficiency of A} - \text{Efficiency of B} = 3 - 2 = 1 \text{ unit per hour} \] 5. **Calculate the time taken to fill the cistern:** - Since the total work needed to fill the cistern is 6 units and the net efficiency is 1 unit per hour, we can find the time taken: \[ \text{Time} = \frac{\text{Total Work}}{\text{Net Efficiency}} = \frac{6 \text{ units}}{1 \text{ unit per hour}} = 6 \text{ hours} \] ### Final Answer: It will take 6 hours to fill the cistern when both taps are opened.
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MAHENDRA-PIPE & CISTERN-EXERCISE
  1. One tap can fill a cistern in 2 hours and another can other can empty ...

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  2. A tap can fill a tank in 25 minutes and another can empty it in 50 mi...

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  3. Two taps A and B can fill a tank in 10 hours and 15 hours, respectivel...

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  4. Two pipes A and B can separately empty a cistern in 12 hours and 15 ho...

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  5. Two pipes can fill a tank in 10 hours and 12 hours respectively. While...

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  6. Two pipes A and B can fill a cistern in 24 minutes and 30 minutes, res...

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  7. A cistern has a leak which would empty in 8 hours. A tap is turned on ...

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  8. If two pipes function simultaneously, a tank is filled in 12 hours. On...

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  9. One fill pipe A is 3 times faster than second fill pipe B and takes 32...

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  10. Two pipes A and B can fill a cistern in 4 minutes and 6 minutes respec...

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  11. There are two taps to fill a tank while a third to empty it. When the ...

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  12. A cistern is provided by two taps A and B. A can fill it in 20 minutes...

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  13. Two pipes A and B can separately fill a tank in 6 hours and 8 hours , ...

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  14. A cistern has two taps which fill it in 12 minutes and 15 mintues resp...

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  15. Two taps can separately fill a cistern in 10 minutes and 15 minutes re...

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  16. A water tank is 2/5 th full. Pipe A can fill the tank in 10 minutes an...

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  17. Tap 'A' can fill a water tank in 25 minutes , tap 'B' can fill the sam...

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  18. A pipe can fill a tank in 5 hours and a second pipe can empty it in 4 ...

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  19. A pump can fill a tank with water in 2 hours. Because of a leak in the...

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  20. Two pipe A and B can separately fill a cistern in 60 minutes and 75 mi...

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