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Two pipes A and B can fill a cistern in ...

Two pipes A and B can fill a cistern in 24 minutes and 30 minutes, respectively. There is also an outlet C. If all the three pipes are opened together, the cistern is filled in 20 minutes. How much time will be taken by C to empty the full cistern?

A

30 min

B

40 min

C

45 min

D

50 min

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow these calculations: ### Step 1: Determine the total work The total work can be calculated using the least common multiple (LCM) of the times taken by pipes A, B, and the time taken when all three are opened together. - Pipe A fills the cistern in 24 minutes. - Pipe B fills the cistern in 30 minutes. - When all three pipes are opened together, the cistern is filled in 20 minutes. To find the LCM of 24, 30, and 20: - The prime factorization of 24 is \(2^3 \times 3^1\). - The prime factorization of 30 is \(2^1 \times 3^1 \times 5^1\). - The prime factorization of 20 is \(2^2 \times 5^1\). The LCM is taken by using the highest power of each prime: - For 2: \(2^3\) - For 3: \(3^1\) - For 5: \(5^1\) Thus, LCM = \(2^3 \times 3^1 \times 5^1 = 120\). **Total Work (TW) = 120 units.** ### Step 2: Calculate the efficiencies of pipes A and B - Efficiency of pipe A = Total Work / Time taken by A = \(120 / 24 = 5\) units per minute. - Efficiency of pipe B = Total Work / Time taken by B = \(120 / 30 = 4\) units per minute. ### Step 3: Calculate the combined efficiency of A, B, and C When all three pipes are opened together, the efficiency is: - Efficiency of A, B, and C = Total Work / Time taken when all are opened = \(120 / 20 = 6\) units per minute. ### Step 4: Set up the equation for the efficiency of pipe C Since pipe C is an outlet, its efficiency will be subtracted from the combined efficiency of pipes A and B: - Efficiency of A + Efficiency of B - Efficiency of C = Efficiency of A, B, and C - \(5 + 4 - \text{Efficiency of C} = 6\) ### Step 5: Solve for the efficiency of pipe C - \(9 - \text{Efficiency of C} = 6\) - \(\text{Efficiency of C} = 9 - 6 = 3\) units per minute. ### Step 6: Calculate the time taken by pipe C to empty the cistern To find the time taken by pipe C to empty the full cistern: - Time = Total Work / Efficiency of C = \(120 / 3 = 40\) minutes. ### Final Answer The time taken by pipe C to empty the full cistern is **40 minutes**. ---
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MAHENDRA-PIPE & CISTERN-EXERCISE
  1. Two pipes A and B can separately empty a cistern in 12 hours and 15 ho...

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  2. Two pipes can fill a tank in 10 hours and 12 hours respectively. While...

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  3. Two pipes A and B can fill a cistern in 24 minutes and 30 minutes, res...

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  4. A cistern has a leak which would empty in 8 hours. A tap is turned on ...

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  5. If two pipes function simultaneously, a tank is filled in 12 hours. On...

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  6. One fill pipe A is 3 times faster than second fill pipe B and takes 32...

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  7. Two pipes A and B can fill a cistern in 4 minutes and 6 minutes respec...

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  8. There are two taps to fill a tank while a third to empty it. When the ...

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  9. A cistern is provided by two taps A and B. A can fill it in 20 minutes...

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  10. Two pipes A and B can separately fill a tank in 6 hours and 8 hours , ...

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  11. A cistern has two taps which fill it in 12 minutes and 15 mintues resp...

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  12. Two taps can separately fill a cistern in 10 minutes and 15 minutes re...

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  13. A water tank is 2/5 th full. Pipe A can fill the tank in 10 minutes an...

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  14. Tap 'A' can fill a water tank in 25 minutes , tap 'B' can fill the sam...

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  15. A pipe can fill a tank in 5 hours and a second pipe can empty it in 4 ...

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  16. A pump can fill a tank with water in 2 hours. Because of a leak in the...

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  17. Two pipe A and B can separately fill a cistern in 60 minutes and 75 mi...

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  18. A tap can fill a cistern in 6 hours. After half of the tank is filled,...

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  19. A pump can fill a tank with water in 2 hours. Because of a leak in the...

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  20. Two pipes A and B can fill a tank in 6 hours and 4 hours respectively ...

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