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A cistern is provided by two taps A and ...

A cistern is provided by two taps A and B. A can fill it in 20 minutes and B in 25 minutes. Both the taps are kept open for 5 minutes and then the second is turned off. The cistern will be complete filled in another

A

11 min

B

10 min

C

15 min

D

12 min

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AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow these calculations: ### Step 1: Determine the total work The total work done by the cistern can be represented in terms of the least common multiple (LCM) of the times taken by taps A and B to fill the cistern. - Tap A can fill the cistern in 20 minutes. - Tap B can fill the cistern in 25 minutes. The LCM of 20 and 25 is 100. Therefore, we can consider the total work of the cistern as 100 units. ### Step 2: Calculate the efficiency of each tap Next, we will calculate the efficiency of each tap in terms of units of work done per minute. - Efficiency of Tap A = Total Work / Time taken by A = 100 / 20 = 5 units per minute. - Efficiency of Tap B = Total Work / Time taken by B = 100 / 25 = 4 units per minute. ### Step 3: Calculate the combined efficiency Now, we will find the combined efficiency when both taps A and B are open. - Combined Efficiency of A and B = Efficiency of A + Efficiency of B = 5 + 4 = 9 units per minute. ### Step 4: Calculate the work done in 5 minutes Now, we will calculate how much work is done when both taps are open for 5 minutes. - Work done in 5 minutes = Combined Efficiency × Time = 9 units/minute × 5 minutes = 45 units. ### Step 5: Calculate the remaining work Now we will find out how much work is left to be done after 5 minutes. - Remaining work = Total Work - Work done in 5 minutes = 100 - 45 = 55 units. ### Step 6: Calculate the time taken to fill the remaining work with Tap A only After 5 minutes, Tap B is turned off, and only Tap A continues to fill the cistern. - Since Tap A's efficiency is 5 units per minute, we can calculate the time required to fill the remaining work. Time = Remaining Work / Efficiency of A = 55 units / 5 units per minute = 11 minutes. ### Final Answer The cistern will be completely filled in another **11 minutes** after Tap B is turned off. ---
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MAHENDRA-PIPE & CISTERN-EXERCISE
  1. Two pipes A and B can fill a cistern in 24 minutes and 30 minutes, res...

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  2. A cistern has a leak which would empty in 8 hours. A tap is turned on ...

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  3. If two pipes function simultaneously, a tank is filled in 12 hours. On...

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  4. One fill pipe A is 3 times faster than second fill pipe B and takes 32...

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  5. Two pipes A and B can fill a cistern in 4 minutes and 6 minutes respec...

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  6. There are two taps to fill a tank while a third to empty it. When the ...

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  7. A cistern is provided by two taps A and B. A can fill it in 20 minutes...

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  8. Two pipes A and B can separately fill a tank in 6 hours and 8 hours , ...

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  9. A cistern has two taps which fill it in 12 minutes and 15 mintues resp...

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  10. Two taps can separately fill a cistern in 10 minutes and 15 minutes re...

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  11. A water tank is 2/5 th full. Pipe A can fill the tank in 10 minutes an...

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  12. Tap 'A' can fill a water tank in 25 minutes , tap 'B' can fill the sam...

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  13. A pipe can fill a tank in 5 hours and a second pipe can empty it in 4 ...

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  14. A pump can fill a tank with water in 2 hours. Because of a leak in the...

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  15. Two pipe A and B can separately fill a cistern in 60 minutes and 75 mi...

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  16. A tap can fill a cistern in 6 hours. After half of the tank is filled,...

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  17. A pump can fill a tank with water in 2 hours. Because of a leak in the...

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  18. Two pipes A and B can fill a tank in 6 hours and 4 hours respectively ...

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  19. Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectiv...

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  20. Two pipes A and B can fill a water tank in 20 and 24 minutes respectiv...

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