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Tap 'A' can fill a water tank in 25 minu...

Tap 'A' can fill a water tank in 25 minutes , tap 'B' can fill the same tank in 40 minutes and tap 'C' can empty that tank in 30 minutes. If all the three taps are opened together , in how many minutes will the tank the completely filled up or emptied ?

A

3

B

9

C

12

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine how long it will take for the tank to be filled or emptied when all three taps are opened together. Let's break it down step by step. ### Step 1: Determine the rates of each tap 1. **Tap A** fills the tank in 25 minutes. - Rate of Tap A = 1 tank / 25 minutes = 1/25 tanks per minute. 2. **Tap B** fills the tank in 40 minutes. - Rate of Tap B = 1 tank / 40 minutes = 1/40 tanks per minute. 3. **Tap C** empties the tank in 30 minutes. - Rate of Tap C = 1 tank / 30 minutes = 1/30 tanks per minute. ### Step 2: Calculate the combined rate of all taps When all taps are opened together, we need to consider the filling rates of taps A and B and the emptying rate of tap C. - Combined rate = Rate of A + Rate of B - Rate of C - Combined rate = (1/25) + (1/40) - (1/30) ### Step 3: Find a common denominator To add these fractions, we need a common denominator. The least common multiple (LCM) of 25, 40, and 30 is 600. - Convert each rate: - Rate of A = (1/25) = (24/600) - Rate of B = (1/40) = (15/600) - Rate of C = (1/30) = (20/600) ### Step 4: Calculate the combined rate Now we can add the rates: - Combined rate = (24/600) + (15/600) - (20/600) - Combined rate = (24 + 15 - 20) / 600 = (19/600) tanks per minute. ### Step 5: Determine the time to fill the tank To find out how long it will take to fill the tank, we use the formula: - Time = Total capacity / Combined rate - Assuming the tank capacity is 600 units (as we calculated earlier): - Time = 600 / (19/600) = 600 * (600/19) = 36000 / 19 minutes. ### Step 6: Calculate the final time Now we can calculate the approximate time: - Time ≈ 189.47 minutes. ### Conclusion If all three taps are opened together, the tank will take approximately **189.47 minutes** to fill.
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MAHENDRA-PIPE & CISTERN-EXERCISE
  1. Two pipes A and B can fill a cistern in 24 minutes and 30 minutes, res...

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  2. A cistern has a leak which would empty in 8 hours. A tap is turned on ...

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  3. If two pipes function simultaneously, a tank is filled in 12 hours. On...

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  4. One fill pipe A is 3 times faster than second fill pipe B and takes 32...

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  5. Two pipes A and B can fill a cistern in 4 minutes and 6 minutes respec...

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  6. There are two taps to fill a tank while a third to empty it. When the ...

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  7. A cistern is provided by two taps A and B. A can fill it in 20 minutes...

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  8. Two pipes A and B can separately fill a tank in 6 hours and 8 hours , ...

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  9. A cistern has two taps which fill it in 12 minutes and 15 mintues resp...

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  10. Two taps can separately fill a cistern in 10 minutes and 15 minutes re...

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  11. A water tank is 2/5 th full. Pipe A can fill the tank in 10 minutes an...

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  12. Tap 'A' can fill a water tank in 25 minutes , tap 'B' can fill the sam...

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  13. A pipe can fill a tank in 5 hours and a second pipe can empty it in 4 ...

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  14. A pump can fill a tank with water in 2 hours. Because of a leak in the...

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  15. Two pipe A and B can separately fill a cistern in 60 minutes and 75 mi...

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  16. A tap can fill a cistern in 6 hours. After half of the tank is filled,...

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  17. A pump can fill a tank with water in 2 hours. Because of a leak in the...

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  18. Two pipes A and B can fill a tank in 6 hours and 4 hours respectively ...

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  19. Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectiv...

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  20. Two pipes A and B can fill a water tank in 20 and 24 minutes respectiv...

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