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I started on my bicycle at 7 a.m. to rea...

I started on my bicycle at 7 a.m. to reach a certain place. After going a certain distance by bicycle went out of order. Consequently, I rested for 35 minutes and came back to my house walking all the way. I reached my house at 1 p.m. If my cycling speed is 10 kmph and my walking speed is 1 kmph, then on my bicycle I covered a distance of :

A

A) `4 (61)/(66)` km

B

B) `13 4/9` km

C

C) `14 3/8` km

D

D) `15 (10)/(21)` km

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The correct Answer is:
To solve the problem step-by-step, we will break it down into manageable parts: ### Step 1: Determine the total time spent The total time from 7 a.m. to 1 p.m. is 6 hours. **Hint:** To find the total time, subtract the start time from the end time. ### Step 2: Convert the rest time into hours The rest time is given as 35 minutes. To convert this into hours, we divide by 60: \[ \text{Rest time in hours} = \frac{35}{60} = \frac{7}{12} \text{ hours} \] **Hint:** Remember that there are 60 minutes in an hour. ### Step 3: Calculate the time spent cycling Let \( t \) be the time spent cycling in hours. The time spent walking will then be: \[ \text{Time spent walking} = \text{Total time} - \text{Rest time} - \text{Cycling time} \] This can be expressed as: \[ \text{Time spent walking} = 6 - \frac{7}{12} - t \] **Hint:** Make sure to express all times in the same unit (hours). ### Step 4: Calculate the distance covered The distance covered while cycling can be expressed as: \[ \text{Distance by bicycle} = \text{Speed} \times \text{Time} = 10t \text{ km} \] The distance covered while walking can be expressed as: \[ \text{Distance by walking} = \text{Speed} \times \text{Time} = 1 \left( 6 - \frac{7}{12} - t \right) \text{ km} \] **Hint:** Use the formula for distance, which is speed multiplied by time. ### Step 5: Set up the equation Since the distance covered while cycling and the distance covered while walking back to the house must be equal, we can set up the equation: \[ 10t = 1 \left( 6 - \frac{7}{12} - t \right) \] **Hint:** This equation represents the fact that the distance to the destination is the same regardless of the mode of transport. ### Step 6: Solve the equation First, simplify the right side: \[ 10t = 6 - \frac{7}{12} - t \] Convert 6 into a fraction with a denominator of 12: \[ 10t = \frac{72}{12} - \frac{7}{12} - t \] Combine the fractions: \[ 10t = \frac{65}{12} - t \] Add \( t \) to both sides: \[ 10t + t = \frac{65}{12} \] This simplifies to: \[ 11t = \frac{65}{12} \] Now, solve for \( t \): \[ t = \frac{65}{12 \times 11} = \frac{65}{132} \text{ hours} \] **Hint:** When solving for \( t \), make sure to isolate \( t \) on one side of the equation. ### Step 7: Calculate the distance covered by bicycle Now, substitute \( t \) back into the distance formula: \[ \text{Distance by bicycle} = 10t = 10 \times \frac{65}{132} = \frac{650}{132} \text{ km} \] This can be simplified: \[ \frac{650}{132} = \frac{325}{66} \text{ km} \] **Hint:** Always simplify your final answer if possible. ### Final Answer The distance covered by bicycle is \( \frac{325}{66} \) km.
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I started on my bicycle at 7 a.m. to reach a certain place . After going a certain distance, my bicycle went out of order. Consequently, I rested for 35 minutes and came back to my house walking all the way. I reached my home at 1 p.m. If my cycling speed is 10 kmph and my walking speed is 1 kmph then on my bicycle I covered a distance of 4(61)/(66)k m b. 13 4/9k m c. 14 3/8k m d. 1(10)/(21)k m

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