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How many arrangements can be made of the...

How many arrangements can be made of the letters of the word 'ARRANGEMENT'?

A

2492800

B

249300

C

`2494800`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of arrangements of the letters in the word "ARRANGEMENT", we will follow these steps: ### Step 1: Count the total number of letters The word "ARRANGEMENT" consists of 11 letters. ### Step 2: Identify the repeating letters In the word "ARRANGEMENT", the letters and their frequencies are as follows: - A: 2 - R: 2 - N: 2 - G: 1 - E: 2 - M: 1 - T: 1 ### Step 3: Apply the formula for permutations of multiset The formula for finding the number of arrangements of letters in a word where some letters are repeated is given by: \[ \text{Number of arrangements} = \frac{n!}{p_1! \times p_2! \times p_3! \times \ldots} \] Where: - \( n \) is the total number of letters, - \( p_1, p_2, p_3, \ldots \) are the frequencies of the repeating letters. ### Step 4: Substitute the values into the formula Here, \( n = 11 \) (total letters) and the frequencies of the repeating letters are: - A: 2 - R: 2 - N: 2 - E: 2 Thus, we can write: \[ \text{Number of arrangements} = \frac{11!}{2! \times 2! \times 2! \times 2!} \] ### Step 5: Calculate the factorials Now we need to calculate \( 11! \) and \( 2! \): - \( 11! = 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 39916800 \) - \( 2! = 2 \) ### Step 6: Substitute the factorial values Now substituting the values into the equation: \[ \text{Number of arrangements} = \frac{39916800}{2 \times 2 \times 2 \times 2} = \frac{39916800}{16} \] ### Step 7: Perform the division Now we perform the division: \[ \frac{39916800}{16} = 2494800 \] ### Conclusion Thus, the total number of arrangements of the letters in the word "ARRANGEMENT" is **2494800**. ---
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