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In how many ways can a cricket team of 1...

In how many ways can a cricket team of 11 players be selected out of 16 players if two particular players are to be included and one particular players is to be rejected?

A

715

B

615

C

915

D

515

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of selecting a cricket team of 11 players from a pool of 16 players, where 2 specific players must be included and 1 specific player must be excluded, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Total Players**: We start with a total of 16 players. 2. **Account for Inclusion and Exclusion**: - We have 2 players that must be included in the team. - We have 1 player that must be excluded from the team. 3. **Calculate Available Players**: After including the 2 players and excluding 1 player, we can calculate the number of players available for selection: - Total players = 16 - Players included = 2 - Players excluded = 1 - Therefore, the number of players available for selection = 16 - 2 - 1 = 13 players. 4. **Determine Team Composition**: Since 2 players are already included in the team of 11, we need to select the remaining players: - Total players needed = 11 - Players already included = 2 - Therefore, players still needed = 11 - 2 = 9 players. 5. **Select Players from Available Pool**: Now we need to select 9 players from the 13 available players. This is a combination problem where we use the combination formula: \[ \text{Number of ways} = \binom{n}{r} = \frac{n!}{r!(n-r)!} \] Here, \( n = 13 \) (available players) and \( r = 9 \) (players to select). 6. **Apply the Combination Formula**: We can substitute the values into the formula: \[ \binom{13}{9} = \frac{13!}{9!(13-9)!} = \frac{13!}{9! \cdot 4!} \] 7. **Simplify the Factorials**: We can simplify this expression: \[ \binom{13}{9} = \frac{13 \times 12 \times 11 \times 10}{4 \times 3 \times 2 \times 1} \] 8. **Calculate the Result**: - Calculate the numerator: \( 13 \times 12 = 156 \) - \( 156 \times 11 = 1716 \) - \( 1716 \times 10 = 17160 \) - Calculate the denominator: \( 4! = 24 \) - Therefore, \( \frac{17160}{24} = 715 \). 9. **Final Answer**: Thus, the total number of ways to select the cricket team under the given conditions is **715**.
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