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In how many ways can the letters of the ...

In how many ways can the letters of the word RUSSIA be arranged?

A

360

B

60

C

180

D

64

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of ways the letters of the word "RUSSIA" can be arranged, we will follow these steps: ### Step 1: Identify the total number of letters The word "RUSSIA" consists of 6 letters: R, U, S, S, I, A. ### Step 2: Count the frequency of each letter In the word "RUSSIA": - R appears 1 time - U appears 1 time - S appears 2 times - I appears 1 time - A appears 1 time ### Step 3: Use the formula for permutations of multiset The formula for the number of arrangements of letters in a word where some letters are repeated is given by: \[ \text{Number of arrangements} = \frac{n!}{n_1! \times n_2! \times \ldots \times n_k!} \] Where: - \( n \) is the total number of letters, - \( n_1, n_2, \ldots, n_k \) are the frequencies of the repeated letters. ### Step 4: Apply the formula Here, \( n = 6 \) (total letters), and the frequencies are: - For R: \( n_1 = 1! \) - For U: \( n_2 = 1! \) - For S: \( n_3 = 2! \) - For I: \( n_4 = 1! \) - For A: \( n_5 = 1! \) Thus, we can substitute into the formula: \[ \text{Number of arrangements} = \frac{6!}{1! \times 1! \times 2! \times 1! \times 1!} \] ### Step 5: Calculate the factorials Now we calculate the factorials: - \( 6! = 720 \) - \( 1! = 1 \) - \( 2! = 2 \) ### Step 6: Substitute the values Now substituting these values into the formula: \[ \text{Number of arrangements} = \frac{720}{1 \times 1 \times 2 \times 1 \times 1} = \frac{720}{2} = 360 \] ### Conclusion Therefore, the total number of ways to arrange the letters of the word "RUSSIA" is **360**. ---
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