In an examination it is required to get 55% of the aggregate marks to pass. A Student gets 520 marks and is declared failed by 5% marks. What are the maximum aggregate marks a student can get ?

Options

A. 960
B. 1250
C. 1040
D. Cannot be determined

Answer

To solve the problem step by step, we need to determine the maximum aggregate marks a student can get based on the information provided.

### Step 1: Define the variables
Let the maximum aggregate marks be denoted as \( x \).

### Step 2: Calculate the passing marks
To pass the examination, a student needs to obtain 55% of the aggregate marks. Therefore, the passing marks can be expressed as:
\[ \text{Passing Marks} = 0.55 \times x \]

### Step 3: Understand the student's performance
The student scored 520 marks but failed by 5% of the aggregate marks. This means the student needed 5% more marks to pass. Thus, the marks required to pass can also be expressed as:
\[ \text{Required Marks} = 520 + 0.05 \times x \]

### Step 4: Set up the equation
Since both expressions represent the passing marks, we can set them equal to each other:
\[ 0.55x = 520 + 0.05x \]

### Step 5: Solve for \( x \)
To isolate \( x \), we first subtract \( 0.05x \) from both sides:
\[ 0.55x - 0.05x = 520 \]
\[ 0.50x = 520 \]

Next, divide both sides by 0.50:
\[ x = \frac{520}{0.50} = 1040 \]

### Conclusion
The maximum aggregate marks a student can get is \( x = 1040 \).