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In a triangle ABC, AB = 5 cm, BC = 6 cm ...

In a triangle ABC, AB = 5 cm, BC = 6 cm and CA = 7 cm. If bisectors of `angleA, angleB, angleC` respectively meet sides BC, CA and AB at D. E, F and I be the incentre of the triangle then
What is BD : DC ?

A

`2:1`

B

`11:7`

C

`3:1`

D

`13:5`

Text Solution

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The correct Answer is:
D
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LUCENT PUBLICATION-CENTRE OF TRIANGLE-EXERCISE-6A
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