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Let A, B, C be 3 independent events such...

Let A, B, C be 3 independent events such that `P(A)=1/3,P(B)=1/2,P(C)=1/4`. Then find the probability of exactly 2 events occurring out of 3 events.

A

option 1 = 1/4

B

option 2 = 9/24

C

option 3 = 3/4

D

option 4 = None of these

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The correct Answer is:
To find the probability of exactly 2 out of the 3 independent events A, B, and C occurring, we can follow these steps: ### Step 1: Identify the probabilities of each event and their complements Given: - \( P(A) = \frac{1}{3} \) - \( P(B) = \frac{1}{2} \) - \( P(C) = \frac{1}{4} \) The probabilities of the complements (not occurring) are: - \( P(A') = 1 - P(A) = 1 - \frac{1}{3} = \frac{2}{3} \) - \( P(B') = 1 - P(B) = 1 - \frac{1}{2} = \frac{1}{2} \) - \( P(C') = 1 - P(C) = 1 - \frac{1}{4} = \frac{3}{4} \)
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