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The probabilities that A and B will die ...

The probabilities that A and B will die with in a year are p and q respectively, then the probability that only one of them will be alive at the end of the year is -

A

P + q

B

P + q - pq

C

p + q + pq

D

p + q - 2pq

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The correct Answer is:
To solve the problem, we need to find the probability that only one of A or B will be alive at the end of the year, given that the probabilities of A and B dying within a year are \( p \) and \( q \) respectively. ### Step-by-Step Solution: 1. **Identify the Probabilities**: - The probability that A dies within a year is \( P(A) = p \). - The probability that B dies within a year is \( P(B) = q \). - The probability that A survives (does not die) is \( P(A') = 1 - p \). - The probability that B survives (does not die) is \( P(B') = 1 - q \). 2. **Define the Events**: - We want to find the probability that only one of them is alive at the end of the year. This can happen in two scenarios: - Scenario 1: A dies and B survives. - Scenario 2: A survives and B dies. 3. **Calculate the Probability for Each Scenario**: - For Scenario 1 (A dies and B survives): \[ P(A \text{ dies and } B \text{ survives}) = P(A) \times P(B') = p \times (1 - q) \] - For Scenario 2 (A survives and B dies): \[ P(A' \text{ survives and } B \text{ dies}) = P(A') \times P(B) = (1 - p) \times q \] 4. **Combine the Probabilities**: - Since these two scenarios are mutually exclusive, we can add their probabilities: \[ P(\text{only one alive}) = P(A \text{ dies and } B \text{ survives}) + P(A' \text{ survives and } B \text{ dies}) \] \[ = p(1 - q) + (1 - p)q \] 5. **Simplify the Expression**: - Expanding the expression: \[ = p - pq + q - pq \] \[ = p + q - 2pq \] 6. **Final Result**: - Therefore, the probability that only one of them will be alive at the end of the year is: \[ P(\text{only one alive}) = p + q - 2pq \] ### Answer: The probability that only one of them will be alive at the end of the year is \( p + q - 2pq \).
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