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India and Pakistan play a 5 match test s...

India and Pakistan play a 5 match test series of hockey, the probability that India wins at least three matches is

A

`1/2`

B

`3/5`

C

`4/5`

D

None of these

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The correct Answer is:
To find the probability that India wins at least three matches in a 5-match test series against Pakistan, we can use the binomial probability formula. ### Step-by-Step Solution: 1. **Define the Probability of Winning and Losing:** Let \( P \) be the probability that India wins a match. Since there are only two outcomes (win or lose), if we assume the probability of winning a match is \( \frac{1}{2} \), then the probability of losing a match \( Q \) is also \( \frac{1}{2} \). 2. **Identify the Required Outcomes:** We need to calculate the probability of India winning at least 3 matches. This includes the scenarios where India wins 3, 4, or 5 matches. 3. **Use the Binomial Probability Formula:** The binomial probability formula is given by: \[ P(X = k) = \binom{n}{k} P^k Q^{n-k} \] where: - \( n \) = total number of matches (5) - \( k \) = number of matches won - \( P \) = probability of winning a match - \( Q \) = probability of losing a match 4. **Calculate the Probability for Winning 3 Matches:** \[ P(X = 3) = \binom{5}{3} \left(\frac{1}{2}\right)^3 \left(\frac{1}{2}\right)^{5-3} = \binom{5}{3} \left(\frac{1}{2}\right)^5 \] \[ = 10 \cdot \frac{1}{32} = \frac{10}{32} \] 5. **Calculate the Probability for Winning 4 Matches:** \[ P(X = 4) = \binom{5}{4} \left(\frac{1}{2}\right)^4 \left(\frac{1}{2}\right)^{5-4} = \binom{5}{4} \left(\frac{1}{2}\right)^5 \] \[ = 5 \cdot \frac{1}{32} = \frac{5}{32} \] 6. **Calculate the Probability for Winning 5 Matches:** \[ P(X = 5) = \binom{5}{5} \left(\frac{1}{2}\right)^5 \left(\frac{1}{2}\right)^{5-5} = \binom{5}{5} \left(\frac{1}{2}\right)^5 \] \[ = 1 \cdot \frac{1}{32} = \frac{1}{32} \] 7. **Sum the Probabilities:** Now, we sum the probabilities of winning 3, 4, and 5 matches: \[ P(X \geq 3) = P(X = 3) + P(X = 4) + P(X = 5) \] \[ = \frac{10}{32} + \frac{5}{32} + \frac{1}{32} = \frac{16}{32} = \frac{1}{2} \] 8. **Final Result:** The probability that India wins at least 3 matches is \( \frac{1}{2} \).
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