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A four digit number is formed by the dig...

A four digit number is formed by the digits 1, 2, 3, 4 with no repetition. The probability that the number is odd is

A

zero

B

`1/3`

C

`1/4`

D

None of these

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The correct Answer is:
To solve the problem of finding the probability that a four-digit number formed by the digits 1, 2, 3, and 4 (with no repetition) is odd, we will follow these steps: ### Step 1: Calculate the total number of four-digit numbers that can be formed. Since we have 4 distinct digits (1, 2, 3, 4), the total number of different four-digit numbers that can be formed is given by the factorial of the number of digits: \[ \text{Total numbers} = 4! = 4 \times 3 \times 2 \times 1 = 24 \] **Hint:** Remember that the factorial of a number \( n \) (denoted \( n! \)) is the product of all positive integers up to \( n \). ### Step 2: Identify the criteria for the number to be odd. A four-digit number is odd if its last digit is an odd number. In our case, the odd digits available are 1 and 3. ### Step 3: Calculate the number of odd four-digit numbers. We will consider two cases based on the last digit being either 1 or 3. #### Case 1: Last digit is 1 - If the last digit is fixed as 1, we can use the remaining digits (2, 3, 4) to fill the first three positions. - The number of arrangements of the remaining three digits is given by \( 3! \): \[ \text{Numbers with last digit 1} = 3! = 3 \times 2 \times 1 = 6 \] #### Case 2: Last digit is 3 - If the last digit is fixed as 3, we can use the remaining digits (1, 2, 4) to fill the first three positions. - Again, the number of arrangements of the remaining three digits is given by \( 3! \): \[ \text{Numbers with last digit 3} = 3! = 3 \times 2 \times 1 = 6 \] ### Step 4: Calculate the total number of odd numbers. Now, we can add the results from both cases: \[ \text{Total odd numbers} = 6 + 6 = 12 \] ### Step 5: Calculate the probability that a number is odd. The probability \( P \) that a randomly formed four-digit number is odd is given by the ratio of the number of odd numbers to the total number of four-digit numbers: \[ P(\text{odd}) = \frac{\text{Total odd numbers}}{\text{Total numbers}} = \frac{12}{24} = \frac{1}{2} \] ### Conclusion The probability that a four-digit number formed by the digits 1, 2, 3, and 4 (with no repetition) is odd is: \[ \boxed{\frac{1}{2}} \]
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