In throwing of two dice, what is the number of exhaustive events ?

Options

A. 6
B. 12
C. 36
D. 18

Answer

To solve the question regarding the number of exhaustive events when throwing two dice, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Problem**: We need to find the total number of outcomes when two dice are thrown. Each die has 6 faces, numbered from 1 to 6.

2. **Calculate Outcomes for One Die**: When throwing one die, the possible outcomes are:
- 1
- 2
- 3
- 4
- 5
- 6

This gives us a total of 6 outcomes for one die.

3. **Calculate Outcomes for Two Dice**: When throwing two dice, each die operates independently. Therefore, the total number of outcomes can be calculated by multiplying the number of outcomes for the first die by the number of outcomes for the second die.

\[ \text{Total outcomes} = \text{Outcomes for Die 1} \times \text{Outcomes for Die 2} = 6 \times 6 \]

4. **Perform the Calculation**:
\[ 6 \times 6 = 36 \]

5. **Conclusion**: The total number of exhaustive events (total outcomes) when throwing two dice is 36.

### Final Answer:
The number of exhaustive events when throwing two dice is **36**.