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The probability that a student will pass...

The probability that a student will pass in Mathematics is 3/5 and the probability that he will pass in English is 1/3. If the probability that he will pass in both Mathematics and English is 1/8, what is the probability that he will pass in at least one subject?

A

`97/120`

B

`87/120`

C

`53/120`

D

`120/297`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the probability that a student will pass in at least one subject (Mathematics or English). We can use the formula for the probability of the union of two events. ### Step-by-Step Solution: 1. **Identify the Given Probabilities:** - Probability of passing in Mathematics, \( P(M) = \frac{3}{5} \) - Probability of passing in English, \( P(E) = \frac{1}{3} \) - Probability of passing in both subjects, \( P(M \cap E) = \frac{1}{8} \) 2. **Use the Formula for the Probability of the Union of Two Events:** The probability that a student passes in at least one subject is given by: \[ P(M \cup E) = P(M) + P(E) - P(M \cap E) \] Here, \( P(M \cup E) \) represents the probability of passing in either Mathematics or English or both. 3. **Substitute the Given Values into the Formula:** \[ P(M \cup E) = \frac{3}{5} + \frac{1}{3} - \frac{1}{8} \] 4. **Find a Common Denominator:** The least common multiple (LCM) of the denominators 5, 3, and 8 is 120. We will convert each fraction to have this common denominator: - Convert \( \frac{3}{5} \): \[ \frac{3}{5} = \frac{3 \times 24}{5 \times 24} = \frac{72}{120} \] - Convert \( \frac{1}{3} \): \[ \frac{1}{3} = \frac{1 \times 40}{3 \times 40} = \frac{40}{120} \] - Convert \( \frac{1}{8} \): \[ \frac{1}{8} = \frac{1 \times 15}{8 \times 15} = \frac{15}{120} \] 5. **Substitute Back into the Formula:** Now substituting back into the equation: \[ P(M \cup E) = \frac{72}{120} + \frac{40}{120} - \frac{15}{120} \] 6. **Combine the Fractions:** \[ P(M \cup E) = \frac{72 + 40 - 15}{120} = \frac{97}{120} \] 7. **Final Result:** The probability that the student will pass in at least one subject is: \[ P(M \cup E) = \frac{97}{120} \]
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