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If P(A) = 3/7, P(B) = 1/2 and P(A'capB')...

If P(A) = 3/7, P(B) = 1/2 and `P(A'capB')=1//14`, then are A and B are mutually exclusive events?

A

No

B

Yes

C

Either yes or no

D

Cannot be determined

Text Solution

AI Generated Solution

The correct Answer is:
To determine if events A and B are mutually exclusive, we need to analyze the given probabilities and apply the definitions and properties of probability. ### Step-by-Step Solution: 1. **Understand Definitions**: - Mutually exclusive events are events that cannot occur at the same time. This means that the probability of their intersection is zero: \( P(A \cap B) = 0 \). 2. **Given Probabilities**: - \( P(A) = \frac{3}{7} \) - \( P(B) = \frac{1}{2} \) - \( P(A' \cap B') = \frac{1}{14} \) (where \( A' \) and \( B' \) are the complements of A and B respectively) 3. **Use De Morgan's Law**: - According to De Morgan's Law, \( P(A' \cap B') = P((A \cup B)') \). This means that the probability of the complement of the union of A and B is equal to the probability of A' intersection B'. 4. **Calculate \( P(A \cup B) \)**: - Since \( P(A' \cap B') = \frac{1}{14} \), we can find \( P(A \cup B) \) using the relationship: \[ P(A \cup B) + P(A' \cap B') = 1 \] - Substituting the known value: \[ P(A \cup B) + \frac{1}{14} = 1 \] - Therefore: \[ P(A \cup B) = 1 - \frac{1}{14} = \frac{14}{14} - \frac{1}{14} = \frac{13}{14} \] 5. **Use the Formula for Union**: - The formula for the probability of the union of two events is: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \] - We can substitute the known values: \[ \frac{13}{14} = \frac{3}{7} + \frac{1}{2} - P(A \cap B) \] 6. **Convert to a Common Denominator**: - Convert \( P(A) \) and \( P(B) \) to a common denominator (14): \[ P(A) = \frac{3}{7} = \frac{6}{14}, \quad P(B) = \frac{1}{2} = \frac{7}{14} \] - Now substitute: \[ \frac{13}{14} = \frac{6}{14} + \frac{7}{14} - P(A \cap B) \] - Simplifying gives: \[ \frac{13}{14} = \frac{13}{14} - P(A \cap B) \] 7. **Solve for \( P(A \cap B) \)**: - Rearranging gives: \[ P(A \cap B) = 0 \] 8. **Conclusion**: - Since \( P(A \cap B) = 0 \), we conclude that events A and B are mutually exclusive. ### Final Answer: Yes, events A and B are mutually exclusive.
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