Home
Class 14
MATHS
A life insurance company insured 25,000 ...

A life insurance company insured 25,000 young boys, 14,000 young girls and 16,000 young adults. The probability of death within 10 years of a young boy, young girl and a young adult are 0.02, 0.03 and 0.15 respectively. One of the insured persons die. What is the probability that the dead person is a young boy?

A

`36/165`

B

`25/166`

C

`26/165`

D

`32/165`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Calculate the number of young boys who may die within 10 years. The probability of death for a young boy is given as 0.02, and the total number of young boys insured is 25,000. \[ \text{Number of young boys who may die} = \text{Probability of death} \times \text{Total number of young boys} \] \[ = 0.02 \times 25000 = 500 \] ### Step 2: Calculate the number of young girls who may die within 10 years. The probability of death for a young girl is given as 0.03, and the total number of young girls insured is 14,000. \[ \text{Number of young girls who may die} = \text{Probability of death} \times \text{Total number of young girls} \] \[ = 0.03 \times 14000 = 420 \] ### Step 3: Calculate the number of young adults who may die within 10 years. The probability of death for a young adult is given as 0.15, and the total number of young adults insured is 16,000. \[ \text{Number of young adults who may die} = \text{Probability of death} \times \text{Total number of young adults} \] \[ = 0.15 \times 16000 = 2400 \] ### Step 4: Calculate the total number of insured persons who may die. Now, we will add the number of young boys, young girls, and young adults who may die. \[ \text{Total number of deaths} = \text{Number of young boys who may die} + \text{Number of young girls who may die} + \text{Number of young adults who may die} \] \[ = 500 + 420 + 2400 = 3320 \] ### Step 5: Calculate the probability that the dead person is a young boy. The probability that the dead person is a young boy can be calculated using the formula: \[ P(\text{young boy}) = \frac{\text{Number of young boys who may die}}{\text{Total number of deaths}} \] \[ = \frac{500}{3320} \] ### Step 6: Simplify the probability. Now we will simplify the fraction: \[ = \frac{500}{3320} = \frac{25}{166} \] Thus, the probability that the dead person is a young boy is \(\frac{25}{166}\). ---
Promotional Banner

Topper's Solved these Questions

  • PROBABILITY

    DISHA PUBLICATION|Exercise PRACTICE EXERCISE (EXPERT LEVEL)|46 Videos
  • PROBABILITY

    DISHA PUBLICATION|Exercise TEST YOURSELF|15 Videos
  • PROBABILITY

    DISHA PUBLICATION|Exercise PRACTICE EXERCISE (FOUNDATION LEVEL)|83 Videos
  • PERMUTATIONS AND COMBINATIONS

    DISHA PUBLICATION|Exercise TEST YOURSELF|15 Videos
  • PROFIT, LOSS AND DISCOUNT

    DISHA PUBLICATION|Exercise Test Yourself|15 Videos

Similar Questions

Explore conceptually related problems

An insurance company insured 2000 scooter drivers,4000 car drivers and 6000 truck drivers.The probability of an accident involving a scooter,a car and a truck are 0.010.03 and 0.15 respectively.One of the insured persons meets with an accident.What is the probability that he is a scooter driver.

An insurance company insured 2000 scooter drivers,4000 car drivers and 6000 truck drivers.The probabilities of an accident for them are 0.01,0.03 and 0.15 respectively.One of the insured persons meets with an accident. What is the probability that he is a scooter driver or a car driver?

An insurance company insured 3000 scooters, 4000 cars and 5000 trucks. The probabilities of the accident involving a scooter, a card and a truck are 0.02, 0.03 and 0.04 respectively. One of the insured vehicles meet with an accident. Find the probability that it is a i. scooter ii. car iii. truck.

An insurance company insured 2000 scooter drivers,4000 car drivers and 6000 truck drivers.The probability of an accidents are 0.01,0.03 and 0.15 respectively.One of the insured persons meets with an accident.What is the probability that he is a scooter driver?

In steel, the Young's modulus and the strain at the breaking point are 2xx10^11Nm^-2 and 0.15 respectively the stress at the break point for steel is

Three wires P, Q and R of the same material and length have radii 0.1 cm, 0.2 cm and 0.3 cm respectively. Which wire has the highest value of Young's modulus of elasticity?

Read the following passages carefully and answer the questions that follow. The modern youth are more intelligent and hardworking than the previous generations. They have more facilities for education and they do utilise them. But they lack proper direction. In the absence of proper guidance, young boys and girls go on increasing their academic qualifications. Some of them secure high percentage of marks whereas most of them get average or below average marks. Since the number of aspirants for a job is much higher than the number of vacancies, most of the young boys and girls do not get any employment. This causes the problem of the educated unemployment and depression among the youth. The problem of the educated unemployed can be solved partly through proper guidance and counseling and partly through grooming. Young students often disregard the advice of their parents and go on imitating their peers. This sets in the chain of the blind leading the blind. Uneducated or semi-educated parents think of academic qualification as achievement. Young students must seek the advice of the school counselors and select a course of study that suit their aptitude. Instead of pursuit of academic excellence, they must go in for proficiency in technical field of information technology, computers, biotechnology, biochemistry and consumer services. In this way their youthful energy will get directed in the proper channel and they may get fruitful employment or become competent enough to launch their own project and give employment to others. What is the positive aspect of today's generation?

DISHA PUBLICATION-PROBABILITY-PRACTICE EXERCISE (STANDARD LEVEL)
  1. Let A and B be two events such that P (bar(AuuB))=1/6, P(AnnB)=1/4and ...

    Text Solution

    |

  2. Seven digits from the numbers 1, 2, 3, 4, 5, 6, 7, 8 and 9 are written...

    Text Solution

    |

  3. A committee of 5 Students is to be chosen from 6 boys and 4 girls. Fin...

    Text Solution

    |

  4. There are 10 envelopes and 10 letters to go inside them. Each letter i...

    Text Solution

    |

  5. A three digit number is written down by random choice of the digits 1 ...

    Text Solution

    |

  6. 4 gentlemen and 4 ladies take seats at random round a table. The proba...

    Text Solution

    |

  7. Two cards are drawn one by one from a pack of cards. The probability o...

    Text Solution

    |

  8. Seven persons are to be seated in a row. The probability that two part...

    Text Solution

    |

  9. The odds against A solving a certain problem are 3 to 2 and the odds i...

    Text Solution

    |

  10. If two events A and B are such that P(A')=0.3, P(B)=0.4 and P(A nn B')...

    Text Solution

    |

  11. If A and B are two events such that P(A) ne 0 and P(B) ne 1 then P(...

    Text Solution

    |

  12. Let 0ltP (A)lt1, 0ltP(B) lt1and P(A uu B)=P(A)+P(B)-P(A)*P(B) then (A...

    Text Solution

    |

  13. A group of researchers took a fair sample of 1972 children from the ge...

    Text Solution

    |

  14. A life insurance company insured 25,000 young boys, 14,000 young girls...

    Text Solution

    |

  15. Eleven books, consisting of five Engineering books, four Mathematics b...

    Text Solution

    |

  16. 12 persons are seated around a round table. What is the probability th...

    Text Solution

    |

  17. The probability of a bomb hitting a bridge is 1/2 and two direct hits...

    Text Solution

    |

  18. A number is chosen at random from the numbers 10 to 99. By seeing the ...

    Text Solution

    |

  19. The probabilities that a student passes in Mathematics, Physics and Ch...

    Text Solution

    |

  20. Two small squares on a chess board are choosen at random. Find the pro...

    Text Solution

    |