Three capacitors of capacitances 2 pF, 3 pF and 4 pF are connected in parallel. Find
(a) total capacitance of the combination.
(b) charge on each capacitor if the combination is connected to a 100 V supply.

Explanation

(a) As all three capacitors are in parallel.
`therefore` Equivalent capacitance
`=2pF + 3pF + 4pF`
`=9 pF = 9 xx 10^(-12) F`
(b) Charge on 2 pF capacitor, `Q_(1) = C_(1)V`
`=(2 xx 10^(-12)) xx 100 = 2 xx 10^(-10) C`
Charge on 3 pF capacitor,.`Q_(2) = C_(3)V`
`=(3 xx 10^(-12)) xx 100 = 3 xx 10^(-10) C`
Charge on 4 pF capacitor, `Q_(3) = C_(3)V`
`= (4 xx 10^(-12)) xx 100 = 4 xx 10^(-10) C`