Which of the following is less acidic among the given halogen compounds?

Options

A. `CHF _(3)`
B. `CHl _(3)`
C. `CHCl _(3)`
D. `CHB r _(3)`

Answer

B

Explanation

Due to stronger `-I` effect of F than `Cl, CHF _(3)` should be more acidic than `CHCl_(3).` But actually reverse is true. This is due to `C C l _(3) ^(-)` left after the removal of a proton from `CHCl _(3)` is stabilized by resonance due to presence of d-orbitals in Cl than `:CF _(3) ^(-)` left after the removal of a proton from `CHF_(3)` which is not stabilized by resonance due to the absence of d-orbitals on F.