What would happen when a solution of potassium chromate is treated with an excess of dilute nitric acid ?

Options

A. `Cr ^(3+) and Cr _(2) O _(7) ^(2-)` are formed
B. `Cr _(2) O _(7)^(2-) and H _(2) O` are formed
C. `Cr O _(4) ^(2-)` rduced to `Cr ^(3+)`
D. `Cr O _(4) ^(2-)` oxidized to `Cr _(2) O _(7) ^(2-)` only

Answer

B

Explanation

The reaction of `K _(2) Cr O _(4)` with dilute nitric acid is represent as
`2 Cr O _(4) ^(2-) + 2 H ^(+) to Cr _(2) O _(7) ^(2-) + H _(2) O`