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A straight wire of mass 200 g and length...

A straight wire of mass 200 g and length 1.5 m carries a current of 2A. It is suspended in mid-air by a uniform horizontal magnetic field B. The magnitude of B (in tesla) is (assume `g = 9.8 ms^(-2)`)

A

`2`

B

`1.5`

C

`0.55`

D

`0.65`

Text Solution

Verified by Experts

The correct Answer is:
D
Magnetic force on straight wire
`F = Bil sin theta = Bil sin 90^@ - Bil`
For equilibrium of wire in mid-air,
`F = mg`
`Bil = mg `
`therefore B = (mg)/(Bil) = (200 xx 10^(-3) xx 9.8)/(2 xx 1.5) = 0.65 T`
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Knowledge Check

  • A straight wire of mas 200 g and length 1.5 m carries a current of 2 A. It is suspended in mid-air by a uniform horizontal magnetic field B. The magntiude of B ( in tesla) is (Take g = 10 m s-^(2) )

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