Home
Class 12
PHYSICS
A square shaped current loop of side len...

A square shaped current loop of side length L and carrying current I lies in a uniform magnetic field B acting perpendicular to the plane of squre loop and directed inward. The net magnetic force acting on current loop is

A

lBL

B

4 lBL

C

zero

D

2lBL

Text Solution

Verified by Experts

The correct Answer is:
C

Let the current is flowing in anti-clockwise direction as shown in figure.

Now, magnetic force on `AD=F_(1)=ilB` inwards (By Fleming’s left hand rule).
Similarly, magnetic force on `BC=F_(2)=ilB` inwards
Since two forces are equal in magnitude and opposite in direction, therefore, they cancel out each other.
Also, magnetic force on `CD=F_(3)=ilB` inwards (By Fleming’s left hand rule)
Similarly, magnetic force on `AB=F_(4)=ilB` inwards
Again, two forces are equal in magnitude and opposite in direction, therefore, they cancel out each other.
So, the net force on the current loop is 0.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • QUESTION-PAPERS-2012

    BITSAT GUIDE|Exercise Physics|40 Videos
  • QUESTION-PAPERS-2014

    BITSAT GUIDE|Exercise PHYSICS|40 Videos

Similar Questions

Explore conceptually related problems

Current loop in a uniform magnetic field

A conducting circular loop of radius r carries a constant current i.It is placed in a uniform magnetic field B such that B is perpendicular to the plane of the loop. The magnetic force acting on the loop is

Knowledge Check

  • A current carrying loop in a uniform magnetic field will experience

    A
    force only
    B
    torque only
    C
    both torque and force
    D
    neither torque nor force
  • A conducting circular loop of radius r carries a constant current i. It is placed in a uniform magnetic field B such that B is perpendicular to the plane of the loop. The magnetic force acting on the loop is

    A
    zero
    B
    ir B
    C
    `2pi` ir B
    D
    `pi irB`
  • Torque acting on a current loop in a uniform magnetic field is equal to

    A
    `overline(P_(m)) xx overline(B)`
    B
    `overline(P_(m)) xx overline(B^(2))`
    C
    `(overline(P_(m)))/(overline(B))`
    D
    `(overline(P_(m)))/(overline(B^(2)))`
  • Similar Questions

    Explore conceptually related problems

    A conducting circular loop of radius r carries a constant current i. It is placed in a uniform magnetic field B such that B is perpendicular to the plane of loop. What is the magnetic force acting on the loop?

    A circular loop of wire is carring a current i (as shown in the figure). On applying a uniform magnetic field inward perpendicular to the plane of the loop, the loop

    A conducting circular loop of radiius r carries a constant current i . It is placed in a uniform magnetic field vec(B)_(0) such that vec(B)_(0) is perpendicular to the plane of the loop . The magnetic force acting on the loop is

    A conducting circular loop of radius r carries a constant current i. It is placed in a uniform magnetic field vecB _(0) such that vec B _(0) is perpendicular to the plane of the loop. The magnetic force acting on the loop is

    A conducting circular loop of radius r carries a constant i. It is placed in a uniform magnetic field B such that B is perpendiclar to the plane of thre loop is .What is the magnetic force acting on the loop?