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How much work must be done by a force on...

How much work must be done by a force on 50 kg body in order to accelerate it from rest to 20m/s in 10s?

A

`10^3 J`

B

`10^4 J`

C

`2 xx 10^3 J`

D

`5 xx 10^4 J`

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The correct Answer is:
To solve the problem of how much work must be done by a force on a 50 kg body to accelerate it from rest to 20 m/s in 10 seconds, we can follow these steps: ### Step 1: Determine the acceleration of the body We know the initial velocity (u) is 0 m/s (since the body starts from rest), the final velocity (v) is 20 m/s, and the time (t) is 10 seconds. We can use the first equation of motion: \[ v = u + at \] Substituting the known values: \[ 20 = 0 + a \cdot 10 \] Solving for acceleration (a): \[ a = \frac{20}{10} = 2 \, \text{m/s}^2 \] ### Step 2: Calculate the force acting on the body Using Newton's second law, the force (F) can be calculated using the formula: \[ F = m \cdot a \] where m is the mass of the body (50 kg) and a is the acceleration we just calculated (2 m/s²): \[ F = 50 \cdot 2 = 100 \, \text{N} \] ### Step 3: Calculate the displacement of the body To find the displacement (s) during the acceleration, we can use the second equation of motion: \[ s = ut + \frac{1}{2} a t^2 \] Since the initial velocity (u) is 0: \[ s = 0 \cdot 10 + \frac{1}{2} \cdot 2 \cdot (10)^2 \] Calculating the displacement: \[ s = \frac{1}{2} \cdot 2 \cdot 100 = 100 \, \text{m} \] ### Step 4: Calculate the work done by the force The work done (W) is given by the formula: \[ W = F \cdot s \] Substituting the values of force and displacement: \[ W = 100 \cdot 100 = 10,000 \, \text{J} \] ### Final Answer The work done by the force on the body is **10,000 Joules**. ---

To solve the problem of how much work must be done by a force on a 50 kg body to accelerate it from rest to 20 m/s in 10 seconds, we can follow these steps: ### Step 1: Determine the acceleration of the body We know the initial velocity (u) is 0 m/s (since the body starts from rest), the final velocity (v) is 20 m/s, and the time (t) is 10 seconds. We can use the first equation of motion: \[ v = u + at \] ...
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