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A body is thrown vertically upwards from...

A body is thrown vertically upwards from `A`. The top of a tower . It reaches the ground in time `t_(1)`. It it is thrown vertically downwards from `A` with the same speed it reaches the ground in time `t_(2)`, If it is allowed to fall freely from `A`. then the time it takes to reach the ground.
.

A

`t=(t_(1)+t_(2))/(2)`

B

`t=(t_(1)-t_(2))/(2)`

C

`t=sqrt(t_(1)t_(2))`

D

`t=sqrt((t_(1))/(t_(2)))`

Text Solution

Verified by Experts

The correct Answer is:
C
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A body is thrown vertically upwards from A . The top of a tower . It reaches the fround in time t_(1) . It it is thrown verically downwards from A with the same speed it reaches the ground in time t_(2) , If it is allowed to fall freely from A . then the time it takes to reach the ground. .

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Knowledge Check

  • From the top of a tower a stone is thrown up which reaches the ground in time t_(1) . A second stone thrown down with the same speed reaches the ground in a time t_(2) . A third stone released from rest from the same location reaches the ground in a time t_(3) . then:

    A
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    B
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    C
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    A
    `v/g[1+sqrt(1+(2gh)/(v^(2)))]`
    B
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    C
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    D
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