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In YDSE, light of wavelength lamda = 500...

In YDSE, light of wavelength `lamda = 5000 Å` is used, which emerges in phase from two slits distance `d = 3 xx 10^(-7) m` apart. A transparent sheet of thickness `t = 1.5 xx 10^(-7) m`, refractive index `n = 1.17`, is placed over one of the slits. Where does the central maxima of the interference now appear from the center of the screen? (Find the value of y?)

A

`4.9^(@) "and " (D(mu-1)t)/(2d)`

B

`4.9^(@)"and " (D (mu-1)t)/(d)`

C

`3.9^(@) "and " (D (mu+1)t)/(d)`

D

`2.9^(@) "and " (2D (mu+1)t)/(d)`

Text Solution

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The correct Answer is:
B
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