Vertical displacement of a plank with a body of mass `'m'` on it is varying according to law `y=sin omegat +sqrt(3) cos omegat`. The minimum value of `omega` for which the mass just breaks off the plank and the moment it occurs first after `t=0` are given by: `(y "is positive vertically upwards")`

Options

A. `sqrt(g//2) , (sqrt(2))/(6) (pi)/(sqrt(g))`
B. `(g)/(sqrt(2)) , (2)/(3) sqrt(pi //g)`
C. `sqrt(g//2), (pi)/(3) sqrt(2//g)`
D. `sqrt(2g), sqrt(2pi//3g)`

Answer

A