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ABCD is a trapezium length of whose para...

ABCD is a trapezium length of whose parallel sides AB and CD are respectively 10 cm and 12 cm. If midpoint of AD and BC are respectively E and F then length of EF is.

A

11 cm

B

more than 11 cm

C

less than 11 cm

D

nothing can be said

Text Solution

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The correct Answer is:
To find the length of EF in trapezium ABCD, where AB and CD are the parallel sides, we can follow these steps: ### Step 1: Identify the lengths of the parallel sides Given: - Length of AB = 10 cm - Length of CD = 12 cm ### Step 2: Use the formula for the length of the line segment joining the midpoints of the non-parallel sides The length of EF, which connects the midpoints E and F of the non-parallel sides AD and BC respectively, can be calculated using the formula: \[ EF = \frac{1}{2} (AB + CD) \] ### Step 3: Substitute the values into the formula Now, substitute the lengths of AB and CD into the formula: \[ EF = \frac{1}{2} (10 \, \text{cm} + 12 \, \text{cm}) \] ### Step 4: Calculate the sum of the lengths Calculate the sum: \[ 10 \, \text{cm} + 12 \, \text{cm} = 22 \, \text{cm} \] ### Step 5: Divide by 2 to find EF Now, divide the sum by 2: \[ EF = \frac{1}{2} \times 22 \, \text{cm} = 11 \, \text{cm} \] ### Final Answer Thus, the length of EF is: \[ \boxed{11 \, \text{cm}} \] ---
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