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If a transversal line cuts two parallel ...

If a transversal line cuts two parallel lines then bisector of internal angle formed a

A

rectangle

B

square

C

rhombus

D

parallelogram

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The correct Answer is:
To solve the question, "If a transversal line cuts two parallel lines, then the bisector of the internal angle formed will create what type of figure?" we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Parallel Lines and Transversal**: - Let’s denote the two parallel lines as line A and line B. - The transversal line that cuts across these two parallel lines can be denoted as line PQ. 2. **Label the Points of Intersection**: - Let the point where line PQ intersects line A be point R and where it intersects line B be point S. 3. **Identify the Internal Angles**: - The angles formed at point R (between line A and line PQ) are internal angles. Let’s label these angles as angle 1 and angle 2. - Similarly, at point S, we have angle 3 and angle 4. 4. **Draw the Angle Bisectors**: - The bisector of angle 1 will create a line segment from point R, and the bisector of angle 2 will also create a line segment from point R. - The same applies to angles 3 and 4 at point S. 5. **Label the Bisectors**: - Let the bisector of angle 1 be line RE and the bisector of angle 2 be line RF. - Similarly, let the bisector of angle 3 be line SE and the bisector of angle 4 be line SF. 6. **Analyze the Angles**: - Since angle 1 and angle 2 are equal (as they are bisected), we can say that angle 1 + angle 2 = 180° (straight line). - Therefore, if angle 1 = angle 2, we can express this as 2 * angle 2 = 180°, leading to angle 2 = 90°. 7. **Repeat for Angles at Point S**: - Similarly, for angles at point S, angle 3 + angle 4 = 180°. - Since angle 3 = angle 4, we can express this as 2 * angle 4 = 180°, leading to angle 4 = 90°. 8. **Conclusion About the Figure**: - Since we have established that the angles formed by the bisectors at points R and S are both 90°, we can conclude that the figure formed by lines RE, RF, SE, and SF is a quadrilateral with all angles being 90°. 9. **Determine the Type of Quadrilateral**: - A quadrilateral with all angles equal to 90° is classified as a rectangle. - Since we have two pairs of opposite sides that are equal (due to the properties of parallel lines and angle bisectors), we can conclude that this figure is a rectangle. ### Final Answer: The bisectors of the internal angles formed when a transversal cuts two parallel lines create a rectangle.
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LUCENT PUBLICATION-QUADRILATERAL -Exercise 7A
  1. The quadrilateral formed by joining the mid-points of the sides AB, BC...

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  2. In the adjacent figure ABCD is a quadrilateral. AB, DC are parallel an...

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  3. Let LMNP be a parallelogram and NR be perpendicular to LP. If the area...

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  4. If a transversal line cuts two parallel lines then bisector of interna...

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  5. In a parallelogram ABCD, M is the midpoint of BD and BM is bisector of...

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  6. The angle subtended by side of a parallelogram with pair of other para...

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  7. In a parallelogram ABCD, a side AB is extended to E such that BE = AB....

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  8. ABCD is a square. M is the mid-point of AB and N is the mid-point of B...

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  9. A parallelogram ABCD has sides AB = 24 cm and AD = 16 cm. The distance...

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  10. ABCD is a rhombus. A line passing through C cuts extended line AD and ...

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  11. In a quadrilateral ABCD, with unequal sides if the diagonals AC and BD...

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  12. The length of the diagonal BD of the parallelogram ABCD is 18 cm. If P...

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  13. ABCD is a cyclic trapezium whose sides AD and BC are parallel to each ...

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  14. The ratio of the angle angleA" and "angle B of a non-square rhombus AB...

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  15. If an exterior angle of a cyclic quadrilateral be 50^(@), then the opp...

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  16. ABCD is a cyclic trapezium such that AD || BC. If angle ABC=70^(@), th...

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  17. Each side of a rhombus is 10 cm, the sum of square of its diagonal is

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  18. In a trapezium ABCD, AB is parallel to CD. If E is midpoint of side AD...

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  19. Points E and F are respectively midpoints of sides AB and CD of a rect...

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  20. The area of a parallelogram ABCD is equal to that right angled isoscel...

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