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cot theta + cot (theta+(pi)/(3)) + cot (...

`cot theta + cot (theta+(pi)/(3)) + cot (theta + (2 pi)/(3))` is equal to

A

`- cot 3 theta`

B

`cot 3 theta`

C

`2 cot 3 theta`

D

`3 cot 3 theta`

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The correct Answer is:
To solve the expression \( \cot \theta + \cot \left( \theta + \frac{\pi}{3} \right) + \cot \left( \theta + \frac{2\pi}{3} \right) \), we will follow these steps: ### Step 1: Rewrite the cotangent terms We know that: - \( \cot \left( \theta + \frac{2\pi}{3} \right) = \cot \left( \pi - \left( \frac{\pi}{3} + \theta \right) \right) = -\cot \left( \frac{\pi}{3} + \theta \right) \) So we can rewrite the expression as: \[ \cot \theta + \cot \left( \theta + \frac{\pi}{3} \right) - \cot \left( \frac{\pi}{3} + \theta \right) \] ### Step 2: Use the cotangent addition formula Using the cotangent addition formula: \[ \cot(a + b) = \frac{\cot a \cot b - 1}{\cot a + \cot b} \] Let \( a = \theta \) and \( b = \frac{\pi}{3} \): \[ \cot \left( \theta + \frac{\pi}{3} \right) = \frac{\cot \theta \cot \frac{\pi}{3} - 1}{\cot \theta + \cot \frac{\pi}{3}} \] Since \( \cot \frac{\pi}{3} = \frac{1}{\sqrt{3}} \), we have: \[ \cot \left( \theta + \frac{\pi}{3} \right) = \frac{\cot \theta \cdot \frac{1}{\sqrt{3}} - 1}{\cot \theta + \frac{1}{\sqrt{3}}} \] ### Step 3: Substitute and simplify Now substituting back into our expression: \[ \cot \theta + \frac{\cot \theta \cdot \frac{1}{\sqrt{3}} - 1}{\cot \theta + \frac{1}{\sqrt{3}}} - \frac{\cot \theta \cdot \frac{1}{\sqrt{3}} - 1}{\cot \theta + \frac{1}{\sqrt{3}}} \] Notice that the last two terms cancel out. Thus, we are left with: \[ \cot \theta \] ### Step 4: Final result Thus, the expression simplifies to: \[ \cot \theta \] ### Summary The value of \( \cot \theta + \cot \left( \theta + \frac{\pi}{3} \right) + \cot \left( \theta + \frac{2\pi}{3} \right) \) is equal to \( \cot \theta \).
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