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If system of equation ax + y + z = a, x ...

If system of equation ax + y + z = a, x + by + z = b and x + y + cz = c is inconsistent, then which of the following is correct?

A

abc - a - b - c + 2 = 0

B

abc -a - b - c + 3 = 0,a = 1

C

abc - a - b - c + 3 = 0

D

`abc - a - b - c + 2 = 0,a ne 1,b ne 1,c ne 1`

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The correct Answer is:
To determine the conditions under which the given system of equations is inconsistent, we need to analyze the system of equations: 1. \( ax + y + z = a \) 2. \( x + by + z = b \) 3. \( x + y + cz = c \) ### Step 1: Write the system in matrix form We can express the system of equations in matrix form as follows: \[ \begin{bmatrix} a & 1 & 1 \\ 1 & b & 1 \\ 1 & 1 & c \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} a \\ b \\ c \end{bmatrix} \] ### Step 2: Find the determinant of the coefficient matrix The determinant of the coefficient matrix must be calculated to check for consistency. The determinant is given by: \[ D = \begin{vmatrix} a & 1 & 1 \\ 1 & b & 1 \\ 1 & 1 & c \end{vmatrix} \] Calculating the determinant using the formula for a 3x3 matrix: \[ D = a \begin{vmatrix} b & 1 \\ 1 & c \end{vmatrix} - 1 \begin{vmatrix} 1 & 1 \\ 1 & c \end{vmatrix} + 1 \begin{vmatrix} 1 & b \\ 1 & 1 \end{vmatrix} \] Calculating the 2x2 determinants: 1. \( \begin{vmatrix} b & 1 \\ 1 & c \end{vmatrix} = bc - 1 \) 2. \( \begin{vmatrix} 1 & 1 \\ 1 & c \end{vmatrix} = c - 1 \) 3. \( \begin{vmatrix} 1 & b \\ 1 & 1 \end{vmatrix} = 1 - b \) Substituting these back into the determinant: \[ D = a(bc - 1) - (c - 1) + (1 - b) \] This simplifies to: \[ D = abc - a - c + 1 + 1 - b \] \[ D = abc - a - b - c + 2 \] ### Step 3: Set the determinant equal to zero for inconsistency For the system to be inconsistent, the determinant must equal zero: \[ abc - a - b - c + 2 = 0 \] ### Step 4: Analyze the conditions for inconsistency From the equation \( abc - a - b - c + 2 = 0 \), we can rearrange it to find: \[ abc = a + b + c - 2 \] ### Step 5: Determine the conditions on \( a, b, c \) For the system to be inconsistent, we also need to ensure that at least one of the determinants \( \Delta_1 \) or \( \Delta_2 \) (derived from the modified matrices) is non-zero. If \( a = 1, b = 1, c = 1 \), then the determinant \( D \) becomes zero, leading to a consistent system. Therefore, for inconsistency, we require: - \( a \neq 1 \) - \( b \neq 1 \) - \( c \neq 1 \) ### Conclusion Thus, the correct answer is that the system of equations is inconsistent if \( a, b, c \) are not equal to 1.
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