The value of current I as shown in the given circuit diagram is

Options

A. 2A
B. `1.5 A `
C. `0.9 A `
D. `0.2 A `

Answer

A

Explanation

The given circuit can be redrawn as

Since `(R_(AB))/(R_(BC)) = (R_(AD))/(R_(DC)) = (1)/(2)` hence, it is a balanced Wheatstone bridge, therefore current flowing in arm BD = 0
`:. R_(eq) = (10 +20) || (6+12) =30 ||18`
`= (30xx18)/(30+18) = 11.25 Omega`
`:. I = (V)/(R_(eq))= (10)/(11.25) =0.89 A ~~0.9 A `