When a capacitor is fully charged as shown in the following figure, then current drawn from the cell is

Options

A. 1 mA
B. 0.5 mA
C. 2 mA
D. 5 mA

Answer

C

Explanation

When capacitor is fully charged, then it acts like a open switch, therefore 8 kW resistor has no use. So, rest of the resistances 4 kW, 7kW and 9 kW will be in series. Hence, current drawn from cell
`l = (10)/((4+7+9)xx10^(3))=(10)/(20xx 10^(3)) = 0.5 mA `