A carbon resistor of (56 `pm` 5.6) k`Omega` is to be marked with rings of different colours for its identification. The colour code sequence will be

Options

A. green, blue, orange, silver
B. blue, yellow, orange, silver
C. green, red, orange, silver
D. red, green, blue, gold

Explanation

To solve the problem of determining the color code sequence for a carbon resistor of (56 ± 5.6) kΩ, we need to follow these steps:

### Step-by-Step Solution:

1. **Identify the Resistance Value**:
The nominal resistance value is given as 56 kΩ. This can be expressed in ohms as:
\[ R = 56 \, k\Omega = 56 \times 10^3 \, \Omega = 56000 \, \Omega \]

2. **Determine the Significant Digits**:
The significant digits of the resistor value are 5 and 6. Therefore, we will use these digits for the color coding.

3. **Identify the Multiplier**:
The resistance value is in kilo-ohms (kΩ), which means we need to express it in terms of a multiplier. Since 1 kΩ = \(10^3\) Ω, the multiplier for our resistor is:
\[ 10^3 \, \text{(which corresponds to the color orange)} \]

4. **Determine the Tolerance**:
The tolerance is given as ±5.6 kΩ. To find the percentage tolerance, we calculate:
\[ \text{Tolerance} = \frac{5.6 \, k\Omega}{56 \, k\Omega} \times 100\% = \frac{5.6}{56} \times 100\% = 10\% \]
A tolerance of 10% corresponds to the color silver.

5. **Assign Color Codes**:
Now we can assign the color codes based on the significant digits, multiplier, and tolerance:
- The first significant digit (5) corresponds to **Green**.
- The second significant digit (6) corresponds to **Blue**.
- The multiplier \(10^3\) corresponds to **Orange**.
- The tolerance of 10% corresponds to **Silver**.

6. **Final Color Code Sequence**:
Therefore, the complete color code sequence for the resistor is:
- **Green** (5)
- **Blue** (6)
- **Orange** (multiplier \(10^3\))
- **Silver** (tolerance 10%)

### Conclusion:
The color code sequence for the carbon resistor of (56 ± 5.6) kΩ is **Green, Blue, Orange, Silver**.

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