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The freezing point (in ""^(@)C) for a so...

The freezing point (in `""^(@)C`) for a solution containing 0.1 g of `K_(3)[Fe(CN)_(6)]` (mol wt 329) in 100 g water `(K_(f)=1.86K kg"mol"^(-1)0` is

A

273.127K

B

272.92K

C

273.023K

D

273.173K

Text Solution

Verified by Experts

The correct Answer is:
A
The depression in freezing point is given by `Delta T_(f)= iK_(f)m` where i can be calculated if we consider the following reaction
`K_(3) [Fe(CN)_(6)] rarr 3K^(+) + [Fe(CN)_(6)]^(3-)`
we can calculate `i=3+1=4`
`Delta T_(f)= I xx K_(f) xx (w_(B))/(M_(B))xx (1000)/(W_(A))= 4 xx 1.86 xx (0.1)/(329) xx (1000)/(100)==0.0226 = 2.26 xx 10^(-2) = 0.023^(@)C 273.127K`
Freezing point of the solution `= -2.3 xx 10^(-2) ""^(@)C` (as freezing point of water is `0^(@)C`)
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