Six years before, the age of mother was numerically equal to the square of son's age. Three years hence, her age will be thrice the age of her son then. Find the present ages of the mother and son.
Write mother's age six years before.

Six years before, the age of mother was numerically equal to the square of son's age. Three years hence, her age will be thrice the age of her son then. Find the present ages of the mother and son. Write their present ages.

Six years before, the age of mother was numerically equal to the square of son's age. Three years hence, her age will be thrice the age of her son then. Find the present ages of the mother and son. Form a quadratic equation from the given condition and solve it.

The sum of father's age and twice the age of his son is 70. If we double the age of the father and add it to the age of his son the sum is 95. Find their present ages.

The sum of father's age and twice the age of his son is 70. If we double the age of the father and add it to the age of his son the sum is 95. Find their present ages.

The ratio of the present ages of mother and son is 12:5 The mother 's age at the time of birthe of the son was 21 years. Find the present ages.

The sum of father's age and twice the age of his son is 70.If we double the age of the father and add it to the age of his son,the sum is 95.Find their present ages.

The ratio of ages of Abha and her mother is 2:5 At the time of Abha's birth her mother's age was 27 years . Find the present ages of Abha and her mother.

Shabana's age 10 years hence will be twice of Juhi's present age. 6 years ago Shabana's age was 5/3 times Juhi's age at that time. Find their present ages.

Sum of the present ages of Manish and Savita is 31. Manish’s age 3 years ago was 4 times the age of Savita. Find their present ages.