In the process of nuclear fission of `1g` of uranium, the mass lost is `0.90 mg`. The efficiency of fission reactor of power house is `20 %`. To obtain `400 MW` power from the power house, how much uranium (in gram) is required per hour?

In the process of nuclear fission of 1 g uranium, the mass lost is 0.92 mg . The efficiency of power house run by the fission reactor is 10% .To obtain 400 megawatt power from the power house, how much uranium will be required per hour? (c=3xx10^(8) m s^(-1)) .

In the process of nuclear fission of 1g uranium, the mass lost is 0.90 milligram. The efficiency of power station run by it is 10% . To obtain 200 megawatt power from the power station, the uranium required per hour is (c = 3 xx 10^(8)) m/s.

The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to prodice 6.4W power is

The energy released by the fission of one uranium atom is 200 MeV. The number of fissions per second required to produce 3.2 MW of power is :

If in a nuclear fission, piece of uranium of mass 0.5 g is lost, the energy obtained in kWh is.

IF in a nuclear fission, piece of uranium of mass 5.0g is lost, the energy obtained in kWh is

If in nuclear fission, a piece of uranium of mass 6.0 g is lost, the energy obtained (in kWh) is n xx 10^(7) . Find the value of n.

The energy released by the fission of a single uranium nucleus is 200 MeV. The number of fission of uranium nucleus per second required to produce 16 MW of power is (Assume efficiency of the reactor is 50%)

in a nucleri reactor U^(235) undergoes fission releasing energy 100 MeV , the reactor has 20% efficiency and the power produces is 2000 MW . If the reactor is to fuction for 5 yr , find the total mass of uranium required .

Assuming that 200MeV of energy is released per fission of uranium atom, find the number of fission per second required to release one kilowatt power.