`200 (MeV)` of energy can be obtained per fission. In a reactor generating `1000 kW`, the number of NUCLEI under going the fission per second is `3.125xx 10^(n)`. Find `n .`

200 MeV of energy may be obtained per fission of U^235 . A reactor is generating 1000 kW of power. The rate of nuclear fission in the reactor is.

Assuming that 200MeV of energy is released per fission of uranium atom, find the number of fission per second required to release one kilowatt power.

A reactor is generating 1000 kW of power and 200 MeV of energy may be obtained per fission of U^235 The rate of nuclear fission in the reactor is

The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to prodice 6.4W power is

If 200 MeV of energy is released in the fission of 1 nucleus of ._(92)U^(235) , the number of nuclei that undergo fission to produce energy of 10 kWh in 1 s is

(a) Calculate the energy released by the fission of 2g of ._(92)U^(235) in kWh . Given that the energy released per fission is 200MeV . (b) Assuming that 200MeV of enrgy is released per fission of uranium atom, find the number of fissions per second required to released 1 kilowatt power. (c) Find the amount of energy produced in joules due to fission of 1g of ._(92)U^(235) assuming that 0.1% of mass is transformed into enrgy. ._(92)U^(235) = 235 amu , Avogadro number = 6.023 xx 10^(23)

The energy released by the fission of one uranium atom is 200 MeV. The number of fissions per second required to produce 3.2 MW of power is :

The energy released per fission of uranium 235 is about 200 MeV. A reactor using U-235 as fuel is producing 1000 kilowatt power. The number of U-235 nuclei undergoing fission per sec is, approximately-

An explosion of atomic bomb releases an energy of 7.6xx10^(13)J . If 200 MeV energy is released on fission of one .^(235)U atom calculate (i) the number of uranium atoms undergoing fission. (ii) the mass of uranium used in the atom bomb