If for x,y in R, x gt 0, y=log(10)x+log(...

If for x,y `in R`, `x gt 0`, `y=log_(10)x+log_(10)x^(1//3)+log_(10)x^(1//9)+`...........upto `oo` terms and `(2+4+6+........+2y)/(3+6+9+.......+3y)=(4)/(log_(10)x)`, then the ordered pair (x,y) is equal to :

A

`(10^(2),3)`

B

`(10^(6),6)`

C

`(10^(6),9)`

D

`(10^(4),6)`

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