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Let (sinA)/(sinB)=(sin(A-C))/(sin(C-B)),...

Let `(sinA)/(sinB)=(sin(A-C))/(sin(C-B))`, where A , B, C are angles of a triangle ABC. If the lengths of the sides opposite these angles are a,b,c respectively, then

A

`b^(2)-a^(2)=a^(2)+c^(2)`

B

`a^(2),b^(2),c^(2)` are in A.P.

C

`c^(2),a^(2),b^(2)` are in A.P.

D

`b^(2),c^(2),a^(2)` are in A.P.

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