The point P(- 2sqrt6, sqrt3) lies on the...

The point `P(- 2sqrt6, sqrt3)` lies on the hyperbola `(x^2)/(a^2) - (y^2)/(b^2) = 1` having eccentricity `(sqrt5)/2` . If the tangent and normal at P to the hyperbola intersect its conjugate axis at the points Q and R respectively, then QR is equal to :

`6sqrt3`

`3sqrt6`

`4sqrt3`

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